⚡ Quick Revision
Day-before-exam revision. 20 minutes. Everything you need. Nothing you don't.
All Formulas At a Glance
🎯 Projectile Motion
📐 Trajectory & Special Cases
↕ Horizontal Projectile (from h)
🔄 Uniform Circular Motion
⭕ Vertical Circle
↗ Relative Motion
⛰ Inclined Plane Projectile
⚙ Non-Uniform Circular Motion
Remember These Instantly
🟡 "45 is Max"
Range is maximum at 45°. Remember: 45 is the perfect balance between horizontal and vertical. Less angle → too flat. More → too vertical.
🔢 T, H, R ratios for 30-45-60
θ=30°: T=v₀/g, H=v₀²/8g, R=v₀²√3/2g
θ=45°: T=v₀√2/g, H=v₀²/4g, R=v₀²/g
θ=60°: T=v₀√3/g, H=3v₀²/8g, R=v₀²√3/2g
🔵 Complementary = Same R
30° & 60°, 20° & 70°, 15° & 75° — all same range. Different height, different time, SAME range. Simple: sin2θ = sin(180°−2θ).
🔴 Vertical Circle Magic Number
T_bottom − T_top = 6mg. Always. No exceptions. This means if T_top = mg, then T_bottom = 7mg.
⚡ UCM Energy Constant
KE = ½mv² = constant. Work done by centripetal force = 0 (force ⊥ displacement). Speed never changes in UCM.
🌊 Horizontal always constant
In ANY projectile problem (no air resistance): horizontal velocity = constant throughout flight. This is the #1 principle. Never forget.
Test Your Recall
Click each card to reveal the answer. Use arrow buttons to navigate.
What is the time of flight formula for a projectile launched at angle θ?
T = 2v₀ sinθ / g
At the highest point of a projectile, what is the vertical velocity?
vy = 0
What angle gives maximum horizontal range?
θ = 45°
For a horizontal projectile from height h, what is the time to hit ground?
T = √(2h/g)
Formula for centripetal acceleration?
aᶜ = v²/r = ω²r
What is the relationship between T_bottom and T_top in vertical circle?
T_b − T_t = 6mg
Formula: minimum speed at top of vertical circle?
v_top,min = √(gR)
For two simultaneously launched projectiles — what is the relative acceleration?
a_relative = 0
Trajectory equation of a projectile?
y = x tanθ − gx²/(2v₀²cos²θ)
Which angle gives same range? (Not 45°)
θ and (90° − θ)
Direction of velocity in UCM?
Always tangent to the circular path
Formula for change in velocity vector |Δv⃗| in circular arc of angle α?
|Δv⃗| = 2v sin(α/2)
What You Must Know Cold
📌 Core Principles
- Horizontal and vertical motions are independent
- Horizontal velocity = constant (no air resistance)
- Vertical: uniformly accelerated downward (g)
- Trajectory is a parabola
- In UCM: speed constant, velocity changes
- Centripetal acc is always toward center
📌 Number Facts
- θ = 45° → max range = v₀²/g
- θ = 90° → max height = v₀²/2g
- T_b − T_t = 6mg (vertical circle)
- v_top,min = √(gR)
- v_bot,min = √(5gR)
- Complementary angles → same R
📌 Common Mistakes to Avoid
- Centripetal = net force, not extra force
- Time of flight = independent of horizontal v
- Average velocity ≠ average speed in 2D
- Acceleration in UCM ≠ 0 (it's centripetal)
- Discard negative time root
- Sign convention must be consistent
📌 JEE Advanced Must-Knows
- Inclined projectile: rotate axes by α
- Relative projectile: a_rel = 0 → straight line
- Variable acc: use calculus (∫ a dt)
- Vertical circle string vs track
- Conical pendulum: T = 2π√(Lcosθ/g)
✅ Chapter Complete!
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