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Formula & Dimensional Analysis

Every formula with derivation context, dimensional verification, and exam application notes.

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🧮 Projectile Motion Calculator

Components of Initial Velocity

All Exams
vₓ = v₀ cosθ  |  vy = v₀ sinθ
Dimension: [LT⁻¹]
Unit: m/s
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Exam Tip

For θ = 45°: vₓ = vy = v₀/√2. For θ = 30°: vₓ = v₀√3/2, vy = v₀/2. Memorize these — they appear in 60% of projectile MCQs.

Position at Time t

CBSE + NEET
x = v₀cosθ · t  |  y = v₀sinθ · t − ½gt²

These are the parametric equations of the parabolic trajectory. Eliminate t to get the trajectory equation.

Common Error

Forgetting the negative sign in y equation. Always: y = vy₀t minus ½gt² (gravity opposes upward motion).

Velocity at Time t

All Exams
vₓ = v₀cosθ  |  vy = v₀sinθ − gt
Speed: |v| = √(vₓ² + vy²) ; Direction: φ = tan⁻¹(vy/vₓ)

Time of Flight (T)

NEET FavouriteJEE Main
T = 2v₀sinθ / g
Time when the projectile returns to the initial level (y = 0)
Special cases: θ=90°: T=2v₀/g (vertical throw) | θ=45°: T=v₀√2/g

Maximum Height (H)

NEETJEE Main
H = v₀²sin²θ / 2g
Height at which vy = 0
For θ=90°: H_max = v₀²/2g | At θ=45°: H = v₀²/4g

Horizontal Range (R)

All ExamsHigh Freq
R = v₀²sin2θ / g
R_max = v₀²/g at θ = 45°; R is same for θ and (90°−θ)
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R-H Relationship

R = 4H·cotθ. Also: R = 4H when θ = 45°. JEE often gives H and asks R — use this directly.

Equation of Trajectory

JEE AdvJEE Main
y = x tanθ − gx² / (2v₀²cos²θ)
Also written as: y = x tanθ(1 − x/R)

The second form y = x tanθ(1 − x/R) is extremely useful when range R is known. Directly substitute x and find y without calculator.

Horizontal Projectile from Height h

NEET
T = √(2h/g)  |  R = u√(2h/g)  |  v_f = √(u² + 2gh)

🧮 Circular Motion Calculator

Angular Velocity

ω = θ/t = 2π/T = 2πf = v/r
Unit: rad/s | Dimension: [T⁻¹]
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Memory Trick

ω = 2πf — angular velocity increases with frequency. More rotations per second = faster spinning.

Centripetal Acceleration

aᶜ = v²/r = ω²r = vω
Direction: toward center | Dimension: [LT⁻²]

Centripetal Force

F = mv²/r = mω²r = mvω
This is the net force directed toward the center
Conceptual Trap

Centripetal force is NOT a separate force. It is the NET force. For a car on a circular road, friction IS the centripetal force. For a satellite, gravity IS the centripetal force.

Time Period & Frequency

T = 2πr/v = 2π/ω  |  f = 1/T = ω/2π

Non-Uniform Circular Motion — Net Acceleration

a_net = √(aᶜ² + aₜ²)  |  aₜ = dv/dt (tangential)
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JEE Insight

For non-uniform circular motion, the acceleration is not toward the center. JEE tests: at what angle is the net acc to the radius? Answer: tan⁻¹(aₜ/aᶜ).

Relative Velocity

v⃗_AB = v⃗_A − v⃗_B
Velocity of A as seen from B
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Thinking Step

Always work from: "velocity of what, w.r.t whom?" A w.r.t B = v_A minus v_B. NEVER add. Direction matters.

Magnitude of Relative Velocity

|v_AB| = √(v_A² + v_B² − 2v_Av_B cosα)
Where α = angle between v⃗_A and v⃗_B

Special cases:
→ Same direction (α=0°): |v_AB| = |v_A − v_B|
→ Opposite (α=180°): |v_AB| = v_A + v_B
→ Perpendicular (α=90°): |v_AB| = √(v_A² + v_B²)

River-Boat: Minimum Time Path

t_min = d/v_b  |  Drift = v_r × (d/v_b)
Boat aimed perpendicular to river bank

River-Boat: Shortest Path

sinθ = v_r/v_b (possible only if v_b > v_r)
Resultant velocity is perpendicular to bank
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Why Dimensional Analysis Matters in This Chapter

In JEE, if you derive a formula and want to verify it quickly — use dimensional analysis. Also, JEE sometimes gives a formula with unknown powers and asks you to find them using dimensional analysis. This appears in ~1 question per year.

QuantityFormulaDimensionSI Unit
Position / Displacementr⃗ = xî + yĵ[L]m
Velocityv = dr/dt[LT⁻¹]m/s
Accelerationa = dv/dt[LT⁻²]m/s²
Range (R)v₀²sin2θ/g[L]m
Time of Flight (T)2v₀sinθ/g[T]s
Max Height (H)v₀²sin²θ/2g[L]m
Angular Velocity (ω)θ/t or v/r[T⁻¹]rad/s
Centripetal Acc (aᶜ)v²/r or ω²r[LT⁻²]m/s²
Centripetal Force (F)mv²/r[MLT⁻²]N
Time Period (T)2π/ω[T]s

Dimensional Verification Examples

Verify: R = v₀²sin2θ/g

1

LHS: [R] = [L]

2

RHS: [v₀²] = [L²T⁻²], sin2θ is dimensionless, [g] = [LT⁻²]

3

[v₀²/g] = [L²T⁻²] / [LT⁻²] = [L] ✓

✅ Dimensionally consistent

Verify: aᶜ = v²/r

1

LHS: [aᶜ] = [LT⁻²]

2

RHS: [v²/r] = [L²T⁻²] / [L] = [LT⁻²] ✓

✅ Dimensionally consistent

Dimensional Analysis Cannot

✗ Tell you the correct formula if multiple formulas have same dimensions.
✗ Determine dimensionless constants (like 2, π, sin, cos, etc.).
✗ Distinguish between scalar and vector quantities.

← Core Concepts Next: Vector Analysis →