Formula Bank & Dimensional Analysis
Every formula with conditions, dimensions, and when to apply
1. Basic Wave Properties
CBSE NEET JEE MainWhere:
- c = speed of light in vacuum = 3 × 10⁸ m/s
- ν = frequency (Hz)
- λ = wavelength (m)
Dimensional Formula: [LT⁻¹] = [T⁻¹] × [L]
Where:
- v = speed in medium
- n = refractive index (dimensionless)
- λₘ = wavelength in medium = λ/n
Critical Point
Frequency never changes when light enters different medium. Only speed and wavelength change.
2. Interference - Young's Double Slit Experiment
NEET JEE Main JEE AdvPath Difference & Phase Difference
Where:
- Δx = path difference
- d = distance between slits
- D = distance from slits to screen
- y = distance of point P from central maximum
Dimensional Formula: δ is dimensionless (radians)
Conditions for Maxima and Minima
Bright Fringes (Maxima)
δ = 2nπ
y = nλD/d
Where n = 0, ±1, ±2, ±3, ...
Dark Fringes (Minima)
δ = (2n + 1)π
y = (2n + 1)λD/2d
Where n = 0, ±1, ±2, ±3, ...
Fringe Width
Where: β = fringe width (distance between two consecutive bright or dark fringes)
Dimensional Formula: [L]
Units: Usually expressed in mm or cm
Exam Insight
Fringe width β is independent of order n. All fringes (bright and dark) are equally spaced in YDSE. This is the most tested property.
Angular Fringe Width
Dimensional Formula: Dimensionless (radians)
Strategy Tip
If problem asks for "angular position" or mentions "small angle approximation," use angular formulas. If it mentions screen distance D explicitly, use linear position formulas.
3. Intensity Distribution
JEE Main JEE AdvResultant Intensity
Where:
- I = resultant intensity at point P
- I₁, I₂ = intensities from individual sources
- δ = phase difference = (2π/λ)Δx
Special Cases
I = 4I₀ cos²(δ/2)
At Maxima
δ = 2nπ
At Minima
δ = (2n + 1)π
Conceptual Depth
I_max = 4I₀, not 2I₀. This factor of 4 comes from constructive interference: amplitudes add (A + A = 2A), and intensity ∝ amplitude² → (2A)² = 4A² = 4I₀. This confuses many students.
4. Single Slit Diffraction
CBSE NEET JEE MainCondition for Minima
Where:
- a = slit width
- θ = angular position of nth minimum
- n = 1, 2, 3, ... (n ≠ 0, as θ = 0 gives central maximum)
Width of Central Maximum
Linear width: 2y = 2λD/a
Where: D = distance from slit to screen
Common Mistake Alert
Central maximum width = 2λD/a (distance between first minima on both sides). Students often write λD/a which is only half-width. Factor of 2 is crucial.
Width of Secondary Maxima
Note: Secondary maxima are half the width of central maximum
Exam Insight
Questions often ask: "How does central maximum width change if slit width is doubled?" Answer: Width ∝ 1/a, so doubling 'a' halves the width. Inversely proportional relationship.
5. Polarization
NEET JEE Main JEE AdvMalus's Law
Where:
- I = transmitted intensity
- I₀ = incident polarized light intensity
- θ = angle between transmission axes of polarizer and analyzer
θ = 0°
Maximum transmission
θ = 45°
Half intensity
θ = 90°
Complete blocking
Brewster's Law
Where:
- θ_B = Brewster's angle (polarizing angle)
- μ = refractive index of medium
Where θ_r is angle of refraction
Strategy Tip
For glass (n ≈ 1.5), Brewster's angle ≈ 56.3°. Memorize this value—it appears frequently in numerical problems as a checksum for your calculation.
🧮 Quick Calculator
Formula: Width = 2λD/a
Use fringe width calculator with 'a' instead of 'd' and multiply result by 2.