Practice with Timer & Score
Three difficulty levels. Select, time yourself, attempt, then reveal. Track your score honestly — the goal is improvement, not just completion.
📊 Session Score
Target: complete each question in 2–3 minutes. All answers can be found directly from formulas. Focus on showing proper steps in boards format.
A particle executes SHM with time period T = 2π seconds. What is its angular frequency?
A simple pendulum has time period T on Earth. On the Moon (g_moon = g_earth/6), what is the new time period?
In SHM, when is potential energy maximum?
A spring of constant k = 400 N/m is attached to a 1 kg mass. The time period of oscillation is:
The phase difference between displacement and acceleration in SHM is:
Target: 90 seconds per question (NEET pace). For JEE Main MCQ: 2 minutes. For JEE Main numerical: 3 minutes. Don't rush — one wrong MCQ = −1 mark in JEE.
Which of the following functions represents simple harmonic motion?
A spring of spring constant k is cut into 3 equal parts. These 3 parts are connected in parallel. The effective spring constant and new time period for mass m are:
In SHM, the ratio of maximum velocity to maximum acceleration is:
A 2 kg block attached to a spring (k = 200 N/m) performs SHM. At x = 0.05 m from equilibrium, its velocity is 0.3 m/s. The amplitude of SHM is _____ × 10⁻² m.
A pendulum of length L₁ has time period T₁. Another pendulum of length L₂ = 4L₁ has time period T₂. The ratio T₂/T₁ is:
Target: 4–5 minutes per question. These require multi-step analysis. Read the ENTIRE question before attempting. Identify all given information. Work systematically — one step error destroys everything.
A particle of mass 1 kg executes SHM: x = 0.1 sin(10πt + π/6) m. Select all CORRECT statements:
PASSAGE: Two SHMs are: x₁ = 3 sin(ωt) cm and x₂ = 4 cos(ωt) cm. A particle undergoes the resultant of these two SHMs simultaneously.