Home
Coaching Programs
NEET Physics Coaching Delhi JEE Physics Coaching Delhi CBSE Class 11 Physics CBSE Class 12 Physics Online Physics Classes Physics Doubt Solving
Academic Calendar
Online Live Class – XI Online Live Class – XII Online Live Class – Dropper Batch
Locations Near You
Physics Coaching East Delhi Physics Coaching South Delhi Physics Coaching Noida Physics Coaching Gurgaon Physics Coaching Ghaziabad Physics Coaching Indirapuram Physics Coaching Greater Noida
Study Material
Class 11
Units & Measurements Motion in 1D Motion in 2D Laws of Motion Work, Energy & Power Rotational Motion Gravitation Thermal Properties Thermodynamics Oscillations & SHM Waves
Class 12
Electric Charges Capacitors Current Electricity Moving Charges EMI Alternating Current EM Waves Ray Optics Wave Optics Dual Nature Nuclei Semiconductors
Expert Strategy Guides
Improve Physics Numericals Common JEE Mistakes Score 90 in CBSE Physics NEET Prep Strategy Exam Time Management Problem Solving Framework Derivations Step-by-Step Why Students Struggle How Toppers Study Best Way to Revise
Resources & Reference
📐 Physics Formulas & Concepts ⚠️ Common Mistakes & Corrections
Blog & Articles
Physics Doubts Solving Guide Best Way to Study Physics for NEET How to Score 90 in Class 12 Physics Physics Formula Sheet Class 12
Book a Diagnostic Session
📞 Call Now 🎯 Get Your Physics Assessment

Newton's Universal Law of Gravitation

Every particle of matter attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

F = G·m₁·m₂ / r²
G = 6.674 × 10⁻¹¹ N·m²·kg⁻² (Universal Gravitational Constant)
m₁, m₂ = Masses of two particles (kg)
r = Distance between their centres (m)
🔬
Exam Insight

This is an inverse square law. If distance doubles, force becomes 1/4. If masses double, force doubles. JEE always tests this proportionality.

Common Mistake Alert

"r" is measured centre to centre, NOT surface to surface. For spheres, use the full distance between centres. Most students lose marks here in numericals.

Key Properties of Gravitational Force

1

Always Attractive

Unlike electric force, gravitational force is always attractive. There is no "gravitational repulsion" in classical physics.

2

Long Range Force

Acts over infinite distances (theoretically). Even across galaxies — the force just becomes negligibly small.

3

Superposition Principle

Net gravitational force on a body = vector sum of forces due to all other bodies individually. F_net = F₁ + F₂ + F₃ + ...

4

Medium-Independent

Does NOT depend on the medium between the masses. It works the same in vacuum, water, or rock.

🧠
Thinking Step

Why does G have such a tiny value (10⁻¹¹)? Because everyday masses (kg-scale) produce negligible gravitational forces. Only astronomical masses (10²⁴ kg) create detectable gravity. This is why you don't fall toward buildings!

🔬 Derivation: Value of g from Newton's Law
1
Gravitational force on mass m at Earth's surface: F = GMₑm/Rₑ²
2
By Newton's 2nd law: F = mg
3
Equating: mg = GMₑm/Rₑ²
4
Therefore: g = GMₑ/Rₑ² = 9.8 m/s²
✓ This derivation is frequently asked in CBSE (5M) and NEET MCQ.

Kepler's Three Laws of Planetary Motion

These were empirically discovered by Kepler before Newton derived them theoretically. JEE loves mixing all three laws in one problem.

I
Law of Orbits
All planets move in elliptical orbits with the Sun at one focus.
Orbit = Ellipse
Sun at focus F₁
II
Law of Areas
The line joining planet to Sun sweeps equal areas in equal time intervals.
dA/dt = const
= L/2m
III
Law of Periods
The square of the time period is proportional to the cube of the semi-major axis.
T² ∝ a³
T²/a³ = const
T² = (4π²/GM) · a³
T = Time period, a = Semi-major axis
M = Mass of central body (Sun/Earth)
🔬
Exam Insight

Kepler's 2nd law is a consequence of conservation of angular momentum. When planet is closest (perihelion) → speed is maximum. When farthest (aphelion) → speed is minimum. JEE Advanced directly tests this.

Common Mistake Alert

In Kepler's 3rd law: T² ∝ r³ holds for circular orbits (r = radius). For elliptical orbits, replace r with semi-major axis 'a'. Many students confuse r with the orbital radius in elliptical problems.

🔬 Derivation: Kepler's 3rd Law from Newton's Law
1
For circular orbit: Gravitational force = Centripetal force
GMm/r² = mv²/r
2
Orbital speed: v = √(GM/r)
3
Time period: T = 2πr/v = 2πr/√(GM/r)
4
Squaring: T² = 4π²r³/GM
5
Therefore: T² ∝ r³ ✓
★ This full derivation is a CBSE 5-mark question almost every year.
🧠
Thinking Step

The ratio T₁²/r₁³ = T₂²/r₂³ is constant for all planets orbiting the same star. Use this directly in ratio problems without finding GM — saves time in NEET/JEE Main.

🔭 Live Kepler Orbit Visualization

Live animation: Planet sweeping equal areas in equal times (Kepler's 2nd Law)

Variation of Acceleration due to Gravity (g)

This is one of the most tested topics in NEET and JEE Main. Four distinct situations — each with a different formula.

📍 On Earth's Surface
g₀ = GM/R²
g₀ = 9.8 m/s² (standard value)
R = Radius of Earth = 6400 km
🏔️ At Height h
g_h = g₀(1 - 2h/R) for h << R
g_h = GM/(R+h)²
g decreases with altitude. At h=R, g becomes g₀/4.
🕳️ At Depth d
g_d = g₀(1 - d/R)
g decreases linearly with depth.
At Earth's centre (d=R): g = 0
🌀 Due to Earth's Rotation
g' = g₀ - ω²R·cos²λ
λ = latitude. Max effect at equator (λ=0°). No effect at poles (λ=90°).
🔬
Exam Insight – Critical Comparison

Rate of decrease of g: At the same small distance from surface — g decreases faster with altitude than with depth. This is a classic NEET/JEE MCQ trap. The formula shows g_h ∝ (1-2h/R) vs g_d ∝ (1-d/R).

Common Mistake Alert

At the centre of Earth, g = 0 — so your weight = 0. But your mass does NOT change. Also, the approximation formula g_h = g₀(1-2h/R) is only valid when h << R. For h comparable to R, use exact formula.

📐 Derivation: g at Height h (exact & approximate)
1
At height h: g_h = GM/(R+h)²
2
Divide by surface g₀ = GM/R²: g_h/g₀ = R²/(R+h)² = [1 + h/R]⁻²
3
For h << R, using binomial: [1+h/R]⁻² ≈ 1 - 2h/R
4
Therefore: g_h ≈ g₀(1 - 2h/R)
📐 Derivation: g at Depth d
1
Shell theorem: Only mass below the object contributes to gravity at depth d.
2
Mass below: M' = M(R-d)³/R³ (uniform density)
3
Gravity: g_d = GM'/( R-d)² = GM(R-d)/R³
4
Simplify: g_d = g₀(1 - d/R)

Escape Velocity

The minimum velocity required to escape a gravitational field — to reach infinity with zero kinetic energy.

Vₑ = √(2GM/R) = √(2gR)
For Earth: Vₑ ≈ 11.2 km/s
For Moon: Vₑ ≈ 2.4 km/s
Independent of mass & direction of projection
🔬 Derivation from Energy Conservation
1
At surface, total energy: E = ½mv² - GMm/R
2
At infinity (just escapes): E_∞ = 0 (KE=0, PE=0)
3
By energy conservation: ½mv² - GMm/R = 0
4
Solving: v = √(2GM/R) ✓
🧠
Thinking Step

Escape velocity is independent of: (a) the mass of the escaping object (m cancels), (b) direction of projection, (c) the shape of path. It's purely about energy, not direction!

🔬
Exam Insight: JEE Twist

JEE asks: "If a planet has double the radius but same density as Earth, what is its escape velocity?" — Using Vₑ = √(8πGρ/3)·R, Vₑ doubles. This form is key for JEE Advanced.

Common Mistake Alert

Escape velocity ≠ orbital velocity at the surface. Escape velocity = √2 × orbital velocity. Students often confuse the two. Orbital velocity at surface = √(GM/R) = 7.9 km/s for Earth.

Satellites & Orbital Mechanics

Everything from orbital speed to geostationary satellites — a favourite in NEET and JEE Main.

v₀ = √(GM/r) = √(gR²/r)
r = R + h (orbital radius)
T = 2π√(r³/GM)
Near Earth surface: T ≈ 84 min
E_total = -GMm/2r
KE = +GMm/2r  |  PE = -GMm/r
Total energy is always negative (bound system)

Geostationary Satellite

• T = 24 hours (matches Earth's rotation)

• Appears stationary from Earth

• Orbits at h ≈ 36,000 km above equator

• Must orbit in equatorial plane

• Used for: communication, GPS, weather

🔬
Exam Insight

Satellite energy relations: KE = -E, PE = 2E, KE = -½PE. When orbit radius increases: KE decreases, PE increases, Total Energy increases (becomes less negative). This seems paradoxical — it's a classic JEE trap!

Common Mistake Alert

In weightlessness (free fall), everything inside the satellite appears weightless. BUT the satellite is NOT outside Earth's gravitational field — g is still ~8.7 m/s² at 400 km altitude.

Gravitational Potential Energy & Binding Energy

The most conceptually tricky part — negative potential energy, reference at infinity, and binding energy. This is where students lose JEE marks.

U = -GMm/r
Reference: U = 0 at r = ∞
Always negative (attractive force)
Increases (becomes less negative) as r increases
🧠
Thinking Step: Why Negative?

We define PE = 0 at infinity (reference). Work done BY gravity when two masses come from ∞ to r is positive → PE at r must be negative. You gain PE by moving away → need to do positive work to escape.

Binding Energy = GMm/2r (for satellite)
= Minimum energy to free satellite from orbit
= -E_total (since E_total is negative)

Gravitational Potential (V)

V = -GM/r
Potential = PE per unit mass
Units: J/kg = m²/s²
Always negative, zero at infinity
g = -dV/dr
Gravitational field = negative gradient of potential
🔬
Exam Insight: JEE Level

Potential inside a uniform solid sphere: V = -GM(3R²-r²)/2R³ (not tested in CBSE but JEE Advanced may ask this).

Common Mistake Alert

Gravitational PE = mV (scalar). Gravitational Field (g) is a vector. Don't mix up their properties. PE can be added algebraically; field must be added vectorially.

📊 Chapter Progress